document.write( "Question 316242: How do you find the x and y intercepts of a log function?\r
\n" ); document.write( "\n" ); document.write( "Example: f(x) = \"+log%28+2%2C+%28x%2B4%29+%29+\" \r
\n" ); document.write( "\n" ); document.write( "I know that you need to let one variable equal 0 to solve for the other, but I am completely lost when it comes to the log on what to do! I've heard to cancel it out on one side (when solving for x) you need to change the x of the log (the 4 in this case) to an exponent on the base, but I'm not sure...
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Algebra.Com's Answer #226162 by vleith(2983)\"\" \"About 
You can put this solution on YOUR website!
\"f%28x%29+=+log%282%2C%28x%2B4%29%29\"
\n" ); document.write( "\"+y+=+log%282%2C%28x%2B4%29%29\"
\n" ); document.write( "\"2%5Ey+=+x%2B4\"
\n" ); document.write( "Let x = 0
\n" ); document.write( "\"2%5Ey+=+4\"
\n" ); document.write( "\"2%5Ey+=+2%5E2\"
\n" ); document.write( "\"y+=+2\"
\n" ); document.write( "one intercept is (0,2)\r
\n" ); document.write( "\n" ); document.write( "\"2%5Ey+=+x%2B4\"
\n" ); document.write( "\"2%5E0+=+x%2B4\"
\n" ); document.write( "\"1+=+x%2B4\"
\n" ); document.write( "\"x+=+-3\"
\n" ); document.write( "another intercept is (-3,0)\r
\n" ); document.write( "\n" ); document.write( "See this for a plot
\n" ); document.write( "http://www.wolframalpha.com/input/?i=log2%28x%2B4%29
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