document.write( "Question 316149: you are given a two-digit positive integer . if you reverse the digits of your number, the result is a number which is 20% larger than your number . what is your number ? \n" ); document.write( "
Algebra.Com's Answer #226150 by ankor@dixie-net.com(22740)\"\" \"About 
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you are given a two-digit positive integer .
\n" ); document.write( "if you reverse the digits of your number, the result is a number which is 20% larger than your number .
\n" ); document.write( " what is your number ?
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\n" ); document.write( "Let 10x + y = \"the number
\n" ); document.write( "then
\n" ); document.write( "10y + x = the reversed number
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\n" ); document.write( "1.2(10x+y) = 10y + x
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\n" ); document.write( "12x + 1.2y = 10y + x
\n" ); document.write( "12x - x = 10y - 1.2y
\n" ); document.write( "11x = 8.8y
\n" ); document.write( "divide both sides by 11
\n" ); document.write( "x = .8y
\n" ); document.write( "The only single digit value for y that will give an integer value to x, is 5
\n" ); document.write( ".8(5) = 4
\n" ); document.write( "the digits:
\n" ); document.write( "x=4, y=5
\n" ); document.write( "45 is the number (54 is the reversed number)
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\n" ); document.write( "Check: 54/45 = 1.2
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