document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=316048>Question 316048</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A ball is thrown upward with an initial velocity of 32 ft/sec from a height of six feet. The function s(t)=-16t^2+32t+6 gives the height of the ball t seconds after release. Determine the time when the ball is at maximun height, and find that height. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #226098 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=226098\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> s(t) is a downward opening parabola (\"a\" is negative) ; so the maximum is at the vertex , which is on the axis of symmetry\r<BR>\n" );
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document.write( "t = -b / 2a = -32 / 2(-16) = 1\r<BR>\n" );
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document.write( "s(1) = -16(1^2) + 32(1) + 6 = 22 </SPAN>\n" );
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