document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=316023>Question 316023</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the reference angle for theta= 5pi/3? \r<BR>\n" );
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document.write( "I know that 300 degrees= 5pi/3. so this means that theta lies in quadrant four and this means that you subtract theta from 360 degrees. so i'm thinking <BR>\n" );
document.write( "360-300 = 60degrees or pi/3 radians as the answer.\r<BR>\n" );
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document.write( "thanks in advance </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #226064 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=226064\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Or simply remember that 360 degrees = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2pi ALIGN=MIDDLE  ALT=\"2pi\"   DISABLED_style= \"max-width:90%; height:auto;\" > radians. So <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2pi-5pi%2F3=6pi%2F3-5pi%2F3=%286pi-5pi%29%2F3=pi%2F3 ALIGN=MIDDLE  ALT=\"2pi-5pi%2F3=6pi%2F3-5pi%2F3=%286pi-5pi%29%2F3=pi%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" > (which is 60 degrees). Either way, you get the same answer. So good job. </SPAN>\n" );
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