document.write( "Question 316018: find the length of the hypotenuse of the right triangle, side a=25, side b=12 \n" ); document.write( "
Algebra.Com's Answer #226062 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "We basically have this triangle set up:\r
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\n" ); document.write( "\n" ); document.write( "To find the unknown length, we need to use the Pythagorean Theorem.\r
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\n" ); document.write( "\n" ); document.write( "Remember, the Pythagorean Theorem is \"a%5E2%2Bb%5E2=c%5E2\" where \"a\" and \"b\" are the legs of a triangle and \"c\" is the hypotenuse.\r
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\n" ); document.write( "\n" ); document.write( "Since the legs are \"25\" and \"12\" this means that \"a=25\" and \"b=12\"\r
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\n" ); document.write( "\n" ); document.write( "Also, since the hypotenuse is \"x\", this means that \"c=x\".\r
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\n" ); document.write( "\n" ); document.write( "\"a%5E2%2Bb%5E2=c%5E2\" Start with the Pythagorean theorem.\r
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\n" ); document.write( "\n" ); document.write( "\"25%5E2%2B12%5E2=x%5E2\" Plug in \"a=25\", \"b=12\", \"c=x\" \r
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\n" ); document.write( "\n" ); document.write( "\"625%2B12%5E2=x%5E2\" Square \"25\" to get \"625\".\r
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\n" ); document.write( "\n" ); document.write( "\"625%2B144=x%5E2\" Square \"12\" to get \"144\".\r
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\n" ); document.write( "\n" ); document.write( "\"769=x%5E2\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2=769\" Rearrange the equation.\r
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\n" ); document.write( "\n" ); document.write( "\"x=sqrt%28769%29\" Take the square root of both sides. Note: only the positive square root is considered (since a negative length doesn't make sense).\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"x=sqrt%28769%29\" which approximates to \"x=27.731\".
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