document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=315948>Question 315948</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this equation: find the exact value,in radians,of theta if tan= -1/squrert(3) and theta lies in quadrant two?  \r<BR>\n" );
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document.write( "the only thing that i have come up with is that tan 1/squrert(3)  is the same as 30 degree.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #226035 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=226035\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The tan(30) is 1/sqrt(3)<BR>\n" );
document.write( "It quadrant 2, it's 180 - 30 = 150º<BR>\n" );
document.write( "You can check it on most calculators.<BR>\n" );
document.write( "150º = 5pi/6 radians<BR>\n" );
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