document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=36788>Question 36788</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I cannot see to solve this one. Can someone help me out? Thanks!\r<BR>\n" );
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document.write( "Maya has deposited $600 in an account that pays 5.64% interest, compounded continuously. How long will it take for her money to double? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #22603 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=22603\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> USe the formula A=Pe^(rt)<BR>\n" );
document.write( "You want to double the P<BR>\n" );
document.write( "so:<BR>\n" );
document.write( "2(600)=600e^(rt)<BR>\n" );
document.write( "2=e^(0.0564t)<BR>\n" );
document.write( "ln2=0.0564t<BR>\n" );
document.write( "t=ln2/0.0564<BR>\n" );
document.write( "t=12<BR>\n" );
document.write( "Hence, it would take 12 years to double the rate.<BR>\n" );
document.write( "PAul. </SPAN>\n" );
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