document.write( "Question 315979: The length of a rectangle is 3 cm more than 2 times its width. If the area of the rectangle is 93 cm2, find the dimensions of the rectangle. Enter your answers in the blanks. Enter only the numeric values rounded to the nearest thousandth of a centimeter.
\n" ); document.write( "Width = __________cm, Length = _________cm.
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Algebra.Com's Answer #226012 by checkley77(12844) $\"\"$ $\"About$

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L=2W+3
\n" ); document.write( "A=LW
\n" ); document.write( "93=(2W+3)W
\n" ); document.write( "93=2W^2+3W
\n" ); document.write( "2W^2+3W-93=0
\n" ); document.write( " $\"W+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"$
\n" ); document.write( "W=(-3+-SQRT93^3-4*2*-93])/2*2
\n" ); document.write( "W=(-3+-SQRT[9+744])/4
\n" ); document.write( "W=(-3+-SQRT753)/4
\n" ); document.write( "W=(-3+-27.44)/4
\n" ); document.write( "W=(-3+27.44)/4
\n" ); document.write( "W=24.44/4
\n" ); document.write( "W=6.11 ANS. FOR THE WIDTH.
\n" ); document.write( "L=2*6.11+3=12.22+3=15.22 ANS. FOR THE LENGTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "93=15.22*6.11
\n" ); document.write( "93~93 \n" ); document.write( "

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