document.write( "Question 315938: a square has an area of 64 square inches. if the same amount is added to the length and removed from the width, the resulting rectangle has an area of 55 square inches. find the dimensions of the rectangle. steps on how to do the problem. please. \n" ); document.write( "
Algebra.Com's Answer #226001 by josmiceli(19441)\"\" \"About 
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Let \"b\" = the amount in inches added to the length
\n" ); document.write( "Let \"b\" = the amount in inches subtracted from the width
\n" ); document.write( "Let \"a\" = the length of the sides of the original square
\n" ); document.write( "---------------------
\n" ); document.write( "given:
\n" ); document.write( "\"a%5E2+=+64\" in2
\n" ); document.write( "Take the square root of both sides
\n" ); document.write( "\"a+=+8\" in
\n" ); document.write( "\"%288+%2B+b%29%2A%288++-+b%29+=+55\" in2
\n" ); document.write( "\"64+%2B+8b+-+8b+-+b%5E2+=+55\" in2
\n" ); document.write( "\"64+-+b%5E2+=+55\"
\n" ); document.write( "\"b%5E2+=+64+-+55\"
\n" ); document.write( "\"b%5E2+=+9\"
\n" ); document.write( "\"b+=+3\"
\n" ); document.write( "\"8+%2B+b\" = length of rectangle
\n" ); document.write( "\"8+%2B+3+=+11\"
\n" ); document.write( "\"8+-+b\" = width of rectangle
\n" ); document.write( "\"8+-+3+=+5\"
\n" ); document.write( "The dimensions are 5 x 11 in2
\n" ); document.write( "
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