document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=4756>Question 4756</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if a rectangle has an area of 100 and 1 side is 2 feet longer then the other what are the length of the second side? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #2260 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=2260\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let shorter length = x<BR>\n" );
document.write( "so longer length = x+2\r<BR>\n" );
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document.write( "Area of rectangle is x(x+2) = 100, so we get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2+%2B+2x+-+100+=+0 ALIGN=MIDDLE  ALT=\"x%5E2+%2B+2x+-+100+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" >. This does not factorise easily, so use the quadratic formula or complete the square (basically the same thing)...\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2+%2B+2x+=+100 ALIGN=MIDDLE  ALT=\"x%5E2+%2B+2x+=+100\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2+%2B+2x+%2B+1+=+100+%2B+1 ALIGN=MIDDLE  ALT=\"x%5E2+%2B+2x+%2B+1+=+100+%2B+1\"   DISABLED_style= \"max-width:90%; height:auto;\" > --> are you OK that this is the same as the previous line?. The reason for adding the 1 is that the lefthand side can now be factorised nicely to (x+1)^2, so:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x%2B1%29%5E2+=+101 ALIGN=MIDDLE  ALT=\"%28x%2B1%29%5E2+=+101\"   DISABLED_style= \"max-width:90%; height:auto;\" > so now we can take square root of both sides, remembering there are 2 answers:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x%2B1%29+=+%2Bsqrt%28101%29 ALIGN=MIDDLE  ALT=\"%28x%2B1%29+=+%2Bsqrt%28101%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x%2B1%29+=+-sqrt%28101%29 ALIGN=MIDDLE  ALT=\"%28x%2B1%29+=+-sqrt%28101%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "so <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+-1%2Bsqrt%28101%29 ALIGN=MIDDLE  ALT=\"x+=+-1%2Bsqrt%28101%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > --ignore the other answer as this is physically not correct for a length.\r<BR>\n" );
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document.write( "Longer side is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2B+-1%2Bsqrt%28101%29 ALIGN=MIDDLE  ALT=\"2%2B+-1%2Bsqrt%28101%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > --> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2Bsqrt%28101%29 ALIGN=MIDDLE  ALT=\"1%2Bsqrt%28101%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "you can check your answer by multiplying <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-1%2Bsqrt%28101%29 ALIGN=MIDDLE  ALT=\"-1%2Bsqrt%28101%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > by <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2Bsqrt%28101%29 ALIGN=MIDDLE  ALT=\"1%2Bsqrt%28101%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > to see if they equal 100.\r<BR>\n" );
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document.write( "jon.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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