document.write( "Question 315790: 1. Two numebers have a sum of 26. Three times the first less twice the second is 3. Find the numbers.
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document.write( "2. Two numbers differ by 7. Three times the larger is five times the smaller olus 3. Find the length.
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document.write( "3. The length of a rectangle is 7cm more than twice the width. Find the dimensions if the perimeter is 62cm. \n" );
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Algebra.Com's Answer #225965 by mananth(16946)![]() ![]() You can put this solution on YOUR website! 1. Two numebers have a sum of 26. Three times the first less twice the second is 3. Find the numbers.\r \n" ); document.write( "\n" ); document.write( "1.x+y=26 \n" ); document.write( "2.3x-2y=3 \n" ); document.write( "multiply eq1 by 2 and add the equationa \n" ); document.write( "2x+2y+3x-2y=52+3 \n" ); document.write( "5x=55 \n" ); document.write( "x=11 \n" ); document.write( "y=26-11=15 \n" ); document.write( "..\r \n" ); document.write( "\n" ); document.write( "2. Two numbers differ by 7. Three times the larger is five times the smaller olus 3. Find the length.\r \n" ); document.write( "\n" ); document.write( "1.x-y=7 \n" ); document.write( "3x=5y+3 \n" ); document.write( "2.3x-5y=3\r \n" ); document.write( "\n" ); document.write( "multiply eq1 by 5 and add the equations \n" ); document.write( "5x-5y+3x-5y=35+3 \n" ); document.write( "8x=38 \n" ); document.write( "x=4.75 \n" ); document.write( "y=-2.25\r \n" ); document.write( "\n" ); document.write( "3. The length of a rectangle is 7cm more than twice the width. Find the dimensions if the perimeter is 62cm.\r \n" ); document.write( "\n" ); document.write( "let width =x \n" ); document.write( "length = x+7 \n" ); document.write( "Perimeter = 2L+2W \n" ); document.write( "2x+2(x+7) \n" ); document.write( "2x+2x+14=62 \n" ); document.write( "4x=62-14 \n" ); document.write( "4x=48 \n" ); document.write( "x=12cm the width \n" ); document.write( "length = 12+7 =19cm \n" ); document.write( " |