document.write( "Question 315795: If a rectangular parking lot has a length that is 5 yards greater than the width. If the area of the parking lot is 900 square yards. Then what is the length and width. \n" ); document.write( "
Algebra.Com's Answer #225962 by mananth(16946)\"\" \"About 
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let width be x
\n" ); document.write( "length = x+5
\n" ); document.write( "Area = L*W
\n" ); document.write( "x(x+5)=900
\n" ); document.write( "x^2+5x-900=0\r
\n" ); document.write( "\n" ); document.write( "x1= -5+sqrt(25+3600) /2
\n" ); document.write( "x1=27.6
\n" ); document.write( "x2=-5-sqrt(25+3600) /2
\n" ); document.write( "x2=-32.6
\n" ); document.write( "..
\n" ); document.write( "width = 27.6 yards
\n" ); document.write( "length = 32.6 yards
\n" ); document.write( "
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