document.write( "Question 315718: In 1988, bettys birthday was on a cold Wednesday in january. In 1993, on what day did her birthday occur?\r
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Algebra.Com's Answer #225910 by Edwin McCravy(20063)\"\" \"About 
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document.write( "If a given date is on a certain day of the week one year, the following\r\n" );
document.write( "year that date will advance one day of the week if there is (or was) no\r\n" );
document.write( "February 29th between that date and and the next, and it will advance\r\n" );
document.write( "two days if there is (or was) a February 29th between that date the first\r\n" );
document.write( "year and that date the second year.\r\n" );
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document.write( "During the 5 years between that January Wednesday 1n 1988, and that date in\r\n" );
document.write( "1993, there were two February 29ths, one in 1988 and another in 1992, so the\r\n" );
document.write( "date advanced 1 day of the week 3 times and 2 days of the week 2 times, and\r\n" );
document.write( "since 3 + 2*2 = 3+4 = 7, her birthday advanced 7 days from Wednesday, which\r\n" );
document.write( "means her birthday was on Wednesday in 1993.  Choice D)\r\n" );
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document.write( "Edwin
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