document.write( "Question 315627: A long distance trucker traveled 180 miles in one direction during a snow storm. The return trip in rainy weather was accomplished at double the speed and took 5 hours less time. Find the speed going. \n" ); document.write( "
Algebra.Com's Answer #225897 by ankor@dixie-net.com(22740)\"\" \"About 
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A long distance trucker traveled 180 miles in one direction during a snow storm.
\n" ); document.write( " The return trip in rainy weather was accomplished at double the speed and took 5 hours less time.
\n" ); document.write( " Find the speed going.
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\n" ); document.write( "Let s = the speed going
\n" ); document.write( "then
\n" ); document.write( "2s = return speed
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\n" ); document.write( "Write a time equation: time = dist/speed
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\n" ); document.write( "go time - return time = 5 hrs
\n" ); document.write( "\"180%2Fs\" - \"180%2F%282s%29\" = 5
\n" ); document.write( "multiply by 2s, results:
\n" ); document.write( "2(180) - 180 = 2s(5)
\n" ); document.write( "360 - 180 = 10s
\n" ); document.write( "180 = 10s
\n" ); document.write( "s = \"180%2F10\"
\n" ); document.write( "s = 18 mph going
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\n" ); document.write( "check solution by finding the actual times
\n" ); document.write( "180/18 = 10 hrs
\n" ); document.write( "180/36 = 5 hrs
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\n" ); document.write( "differ = 5 hrs
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