document.write( "Question 315740: please help--I've tried this for 2 days.
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Algebra.Com's Answer #225885 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "\"0=9x%5E2%2B24x%2B10\"\r\n" );
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document.write( "\"9x%5E2%2B24x%2B10=0\"\r\n" );
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document.write( "Compare to\r\n" );
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document.write( "\"ax%5E2%2Bbx%2Bc=0\" and find that\r\n" );
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document.write( "\"a=9\", \"b=24\", and \"c=10\"\r\n" );
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document.write( "Then substitute in\r\n" );
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document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\" \r\n" );
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document.write( "\"x+=+%28-24+%2B-+sqrt%28+24%5E2-4%2A9%2A10+%29%29%2F%282%2A9%29+\" \r\n" );
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document.write( "\"x+=+%28-24+%2B-+sqrt%28+576-360+%29%29%2F18+\"\r\n" );
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document.write( "\"x+=+%28-24+%2B-+sqrt%28216+%29%29%2F18+\"\r\n" );
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document.write( "216 is not a perfect square. However it has a perfect square\r\n" );
document.write( "36 as a factor for 36*6 is 216. So we write 36*6 instead of 216\r\n" );
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document.write( "\"x+=+%28-24+%2B-+sqrt%2836%2A6%29%29%2F18+\"\r\n" );
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document.write( "Now to take the square root of the product 36*6 by taking individual \r\n" );
document.write( "square roots of 36 and 6\r\n" );
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document.write( "\"x+=+%28-24+%2B-+sqrt%2836%29sqrt%286%29%29%2F18+\"\r\n" );
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document.write( "Now we know the square root of 36 is 6, so we write 6 instead of \"sqrt%2836%29\".\r\n" );
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document.write( "\"x+=+%28-24+%2B-+6sqrt%286%29%29%2F18+\"\r\n" );
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document.write( "Next we factor 6 out of the top:\r\n" );
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document.write( "\"x+=+%286%28-4+%2B-+sqrt%286%29%29%29%2F18+\"\r\n" );
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document.write( "Finally we cancel the 6 in the top into the 18 in the bottom \r\n" );
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document.write( "\"x+=+%28cross%286%29%28-4+%2B-+sqrt%286%29%29%29%2Fcross%2818%29%5B3%5D+\"\r\n" );
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document.write( "That leaves 3 in the bottom:\r\n" );
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document.write( "\"x+=+%28-4+%2B-+sqrt%286%29%29%2F3+\"\r\n" );
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document.write( "Edwin
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