document.write( "Question 315712: How do I work this equation?\r
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document.write( "2. Suppose that the length of a rectangle is three cm longer than twice the width and that the perimeter of the rectangle is 90 cm.
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document.write( "a) Set up an equation for the perimeter involving only W, the width of the rectangle.
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document.write( "Answer:
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document.write( "b) Solve this equation algebraically to find the length of the rectangle. Find the width as well.
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document.write( " Answer: Length ______, Width ______
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Algebra.Com's Answer #225877 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! The length, L, can be expressed in terms of the width, W, thus: \n" ); document.write( "1) L = 2W+3 \"...the length ...is 3cm longer than twice the width...\" \n" ); document.write( "The perimeter of a rectangle is given by: \n" ); document.write( "2) P = 2L+2W \n" ); document.write( "a) Substitute equation 1) for L in equation 2) \n" ); document.write( "2(2W+3)+2W = P Simplify. \n" ); document.write( "4W+6+2W = P \n" ); document.write( "6W+6 = P or \n" ); document.write( "b) Substitute P = 90 and solve for W. \n" ); document.write( "6W+6 = 90 Subtract 6 from both sides. \n" ); document.write( "6W = 84 Divide both sides by 6. \n" ); document.write( "W = 14 and... \n" ); document.write( "L = 2W+3 \n" ); document.write( "L = 2(14)+3 \n" ); document.write( "L = 31 \n" ); document.write( "Length = 31cm. \n" ); document.write( "Width = 14cm. \n" ); document.write( " |