document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=315579>Question 315579</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I would like to know how would I be able to find the measure of an angle using algebra when the two given angels that you would use for the equation are not congruent.<BR>\n" );
document.write( "The only equation that I am aware of to find the measure of an angle using algebra is <ABC = <DEF, and if the two given angels are not congruent then what formula would be correct to solve the problem?\r<BR>\n" );
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document.write( "Here are two problems, one that has two given angels thare are congruent and one with one of the given angels being half of the other therefore they are not congruent.\r<BR>\n" );
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document.write( "For these problems, QP and QR are oppisite rays that form line PQR, and QT bisects <RQS which meets line PQR at point Q(middle)\r<BR>\n" );
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document.write( "1. If m<RQT = 6x+5 and m<SQT = 7x-2, find m<RQT<BR>\n" );
document.write( "These are both parts/halfs of the angel <SQR so they are congruent and I am able to use the <ABC = <DEF formula to find the measure which would be 47 and x=7<BR>\n" );
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document.write( "This is the one I can't figure out???<BR>\n" );
document.write( "2. Find m<TQS if m<RQS = 22a-11 and m<RQT =12a-8<BR>\n" );
document.write( "<TQS is one half of <RQS but is not given. <RQT is the other half of <RQS and is therefore not congruent to the other given angel but still I tried to use the formula given to me.<BR>\n" );
document.write( "I know what the answer is: The value of x( x=2.5) and the measure of <TQS (m=22) but the formula does not give these results so HOW DO YOU GET THIS ANSWER?(which is the correct answer) I just can't figure out what equation they used in order to solve this.<BR>\n" );
document.write( "When I do it the way I know, I come up with -1.9 which is obviuosly incorrect:<BR>\n" );
document.write( "<ABC = <DEF<BR>\n" );
document.write( "m<RQS = m<RQT<BR>\n" );
document.write( "22a-11 = 12a-8<BR>\n" );
document.write( "   +8            +8<BR>\n" );
document.write( "22a-19 = 12a<BR>\n" );
document.write( "-22a         -22a<BR>\n" );
document.write( "19 = -10a<BR>\n" );
document.write( "19/-10 = -10a/-10a<BR>\n" );
document.write( "-1.9 = a\r<BR>\n" );
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document.write( "Can anyone help me, Please.<BR>\n" );
document.write( "I would greatly appreciate it. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #225856 by </B><A HREF=/tutors/aboutme.mpl?userid=Fombitz><B>Fombitz(32388)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Fombitz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Fombitz><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=225856\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=22a-11%2B8+=+12a-8%2B8 ALIGN=MIDDLE  ALT=\"22a-11%2B8+=+12a-8%2B8\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=22a-3=12a ALIGN=MIDDLE  ALT=\"22a-3=12a\"   DISABLED_style= \"max-width:90%; height:auto;\" > <--- -11+8=-3<BR>\n" );
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