document.write( "Question 315583: Roberto invested some money at 8%, and then invested $3000 more than twice this amount at 9%. HIs total annual income from the two investments was $3130. How much was invested at 9%? A)$25,000 B)$2500 C)$22,000 D)$9000\r
\n" ); document.write( "\n" ); document.write( "I tried by setting my values as follows:
\n" ); document.write( "X=.08X
\n" ); document.write( "Y=.09Y+3000(.08X)
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Algebra.Com's Answer #225852 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
OK, first name your variables.
\n" ); document.write( "Let \"A\" be the amount at 8%,\"+B\" the amount at 9%.
\n" ); document.write( "You know the relationship between A and B.
\n" ); document.write( "1.\"B=3000%2B2A\"
\n" ); document.write( "Also you know the total interest from both of the investments.
\n" ); document.write( "\"0.08A%2B0.09B=3130\"
\n" ); document.write( "Multiply both side by 100 to get rid of decimals.
\n" ); document.write( "\"8A%2B9B=313000\"
\n" ); document.write( "Substitute eq. 1 into eq. 2 and solve for A.
\n" ); document.write( "\"8A%2B9%283000%2B2A%29=313000\"
\n" ); document.write( "\"8A%2B27000%2B18A=313000\"
\n" ); document.write( "\"26A=286000\"
\n" ); document.write( "\"highlight%28+A=11000%29\"
\n" ); document.write( "Then from eq. 1,
\n" ); document.write( "\"B=3000%2B2%2811000%29\"
\n" ); document.write( "\"B=3000%2B22000\"
\n" ); document.write( "\"highlight%28+B=25000%29\"
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