document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=315631>Question 315631</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I find the LENGTH of a CUBOID with the width of 12mm, height of 6cm and the Total Surface Area of 468cm^2\r<BR>\n" );
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document.write( "thanks.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #225840 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=225840\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How do I find the LENGTH of a CUBOID with the width of 12mm, height of 6cm and the Total Surface Area of 468cm^2 <BR>\n" );
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document.write( " 2(L*W) + 2(L*H) + 2(W*H) = S.A.<BR>\n" );
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document.write( "2(12L) + 2(6L) + 2(12*6) = 468<BR>\n" );
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document.write( "24L + 12L + 2(72) = 468<BR>\n" );
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document.write( "36L + 144 = 468<BR>\n" );
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document.write( "36L = 468 - 144<BR>\n" );
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document.write( "36L = 324<BR>\n" );
document.write( "L = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=324%2F36 ALIGN=MIDDLE  ALT=\"324%2F36\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "L = 9 mm is the length<BR>\n" );
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document.write( "You can check solution in the original Surface area equation </SPAN>\n" );
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