document.write( "Question 315464: Two straight roads intersect at right angles. At 10:00 a.m. a car passes through the
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document.write( "intersection headed due east at 30 miles per hour. At 11:00 a.m. a truck heading due
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document.write( "north at 40 miles per hour passes through the intersection. Assume that the two vehicles
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document.write( "maintain the given speeds and directions. At what rate are they separating at 1:00 p.m.? \n" );
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Algebra.Com's Answer #225798 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Two straight roads intersect at right angles. \n" ); document.write( " At 10:00 a.m. a car passes through the intersection headed due east at 30 miles per hour. \n" ); document.write( " At 11:00 a.m. a truck heading due north at 40 miles per hour passes through the intersection. \n" ); document.write( "Assume that the two vehicles maintain the given speeds and directions. \n" ); document.write( " At what rate are they separating at 1:00 p.m.? \n" ); document.write( ": \n" ); document.write( "From the given information: \n" ); document.write( "At 1 pm: \n" ); document.write( "truck travel time = 2 hrs \n" ); document.write( "Car travel time = 3 hrs \n" ); document.write( ": \n" ); document.write( "Find the dist between the vehicles using pythag: c^2 = a^2 + b^2 \n" ); document.write( "Distance at 2 PM \n" ); document.write( "a = 4(30) = 120 mi \n" ); document.write( "b = 3(40) = 120 mi \n" ); document.write( "c = \n" ); document.write( "c = 169.7 mi apart at 2 PM \n" ); document.write( ": \n" ); document.write( "Find the distance at 12 noon \n" ); document.write( "a = 2(30) = 60 mi \n" ); document.write( "b = 1(40) = 40 mi \n" ); document.write( "c = \n" ); document.write( "c = 72.1 mi apart at 12 noon \n" ); document.write( ": \n" ); document.write( "12 noon to 2 pm separation distance: 169.7 - 72.1 = 97.6 mi \n" ); document.write( "Average rate of separation 97.6/2 = 48.8 mph separation rate at 1 pm \n" ); document.write( " |