document.write( "Question 315557: Interest Compounded Continuously.
\n" ); document.write( "Suppose that Po is invested in a savings account where interest is compounded continuity at 3.1% per year. \r
\n" ); document.write( "\n" ); document.write( "A. Express P(t) in terms of Po and 0.031. \r
\n" ); document.write( "\n" ); document.write( "B. Suppose that $1000 is invested. What is the balance after 1 yr? After 2yrs? \r
\n" ); document.write( "\n" ); document.write( "C. When will an investment of $1000 double itself?
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Algebra.Com's Answer #225790 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "A.\r
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\n" ); document.write( "\n" ); document.write( "In general:\r
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\n" ); document.write( "\n" ); document.write( "For a 3.1% interest rate:\r
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\n" ); document.write( "\n" ); document.write( "B. 1 yr:\r
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\n" ); document.write( "\n" ); document.write( "B. 2 yr:\r
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\n" ); document.write( "\n" ); document.write( "The calculator work is left as an exercise for the student.\r
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\n" ); document.write( "\n" ); document.write( "C. The investment will double regardless of the value of the initial investment when , which is to say when, in general, , or specifically for this problem, .\r
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\n" ); document.write( "\n" ); document.write( "Take the natural log of both sides:\r
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\n" ); document.write( "\n" ); document.write( "Use :\r
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\n" ); document.write( "\n" ); document.write( "Use \r
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\n" ); document.write( "\n" ); document.write( "Divide by \r
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\n" ); document.write( "\n" ); document.write( "Is the general solution. The specific solution and the resulting arithmetic are left as an exercise for the student.\r
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\n" ); document.write( "\n" ); document.write( "In a still more general case, the time, , to multiply the principal amount by , with interest rate, , compounded continuously is:\r
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\n" ); document.write( "\n" ); document.write( "By the way, this was 4 problems in one post. You are allowed only 1 problem per post. Read the instructions, that's why they are there.\r
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