document.write( "Question 315472: lynne is currently 100% older than her younger sister sylvie. in 8 years , she will be only 20% older. how old is sylvie now ?\r
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document.write( "a) 2 years b) 4 years c) 10 years d) 20 years e) none \n" );
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Algebra.Com's Answer #225751 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! lynne is currently 100% older than her younger sister sylvie. \n" ); document.write( "this means Lynne is Twice as old as Sylvie \n" ); document.write( "L = 2S \n" ); document.write( ": \n" ); document.write( "in 8 years , she will be only 20% older. \n" ); document.write( "L + 8 = 1.2(S + 8) \n" ); document.write( "L + 8 = 1.2s + 9.6 \n" ); document.write( "L = 1.2s + 9.6 - 8 \n" ); document.write( "L = 1.2s + 1.6 \n" ); document.write( ": \n" ); document.write( "how old is sylvie now ? \n" ); document.write( "Replace L with 2S in the above equation \n" ); document.write( "2S = 1.2s + 1.6 \n" ); document.write( "2s - 1.2s = 1.6 \n" ); document.write( ".8s = 1.6 \n" ); document.write( "s = \n" ); document.write( "s = 2 yrs Sylvie now \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution in the statement (Lynne is 4): \n" ); document.write( "\"in 8 years , she will be only 20% older. \n" ); document.write( "4 + 8 = 1.2(2 + 8) \n" ); document.write( "12 = 1.2(10); confirms our solution of S = 2 \n" ); document.write( " |