document.write( "Question 315531: please help me solve this question:
\n" ); document.write( "y^2+2y=x^2+x
\n" ); document.write( " is this equation a parabola, circle, ellipse, or hyperbola? how do you know?
\n" ); document.write( "thnks
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Algebra.Com's Answer #225746 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
y^2+2y=x^2+x
\n" ); document.write( "is this equation a parabola, circle, ellipse, or hyperbola? how do you know?
\n" ); document.write( "It is a hypobola because the x^2 and y^2 have opposite signs when
\n" ); document.write( "arranged on the same side of the equation.
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\n" ); document.write( "Rearrange:
\n" ); document.write( "x^2 + x - (y^2+2y) = 0
\n" ); document.write( "Complete the square:
\n" ); document.write( "(x^2 + x + (1/2)^2) - (y^2+2y+1) = (1/2)^2 - 1
\n" ); document.write( "(x+1/2)^2 - (y+1)^2 = -3/4
\n" ); document.write( "----
\n" ); document.write( "(y+1)^2 - (x+(1/2))^2 = (3/4)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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