document.write( "Question 315531: please help me solve this question:
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document.write( "y^2+2y=x^2+x
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document.write( " is this equation a parabola, circle, ellipse, or hyperbola? how do you know?
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document.write( "thnks \n" );
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Algebra.Com's Answer #225746 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! y^2+2y=x^2+x \n" ); document.write( "is this equation a parabola, circle, ellipse, or hyperbola? how do you know? \n" ); document.write( "It is a hypobola because the x^2 and y^2 have opposite signs when \n" ); document.write( "arranged on the same side of the equation. \n" ); document.write( "================================================= \n" ); document.write( "Rearrange: \n" ); document.write( "x^2 + x - (y^2+2y) = 0 \n" ); document.write( "Complete the square: \n" ); document.write( "(x^2 + x + (1/2)^2) - (y^2+2y+1) = (1/2)^2 - 1 \n" ); document.write( "(x+1/2)^2 - (y+1)^2 = -3/4 \n" ); document.write( "---- \n" ); document.write( "(y+1)^2 - (x+(1/2))^2 = (3/4) \n" ); document.write( "=============================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=============================== \n" ); document.write( " |