document.write( "Question 130760: Solve \"4x%5E2=12\"\r
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\n" ); document.write( "\n" ); document.write( "Find the x-intercepts of \"f%28x%29=4x%5E2-12\"
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Algebra.Com's Answer #225714 by janjan440(1)\"\" \"About 
You can put this solution on YOUR website!
If we look at the page numbers, we'll notice that they are consecutive integers. So they follow the algebraic form x, x%2B1, x%2B2, etc.\r
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\n" ); document.write( "\n" ); document.write( "So if the product of two consecutive integers is 420, then we have the equation\r
\n" ); document.write( "\n" ); document.write( "x%28x%2B1%29=420\r
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\n" ); document.write( "\n" ); document.write( "x%5E2%2Bx=420 Distribute\r
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\n" ); document.write( "\n" ); document.write( "x%5E2%2Bx-420=0 Subtract 420 from both sides\r
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\n" ); document.write( "\n" ); document.write( "%28x%2B21%29%28x-20%29=0 Factor the left side (note: if you need help with factoring, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "Now set each factor equal to zero:
\n" ); document.write( "x%2B21=0 or x-20=0\r
\n" ); document.write( "\n" ); document.write( "x=-21 or x=20 Now solve for x in each case\r
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\n" ); document.write( "\n" ); document.write( "So our possible solutions are\r
\n" ); document.write( "\n" ); document.write( "x=-21 or x=20\r
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\n" ); document.write( "\n" ); document.write( "However, since a negative page number is not possible, this means that the only solution is x=20\r
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\n" ); document.write( "\n" ); document.write( "Now to find the next page number, simply add 1 to 20 to get\r
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\n" ); document.write( "\n" ); document.write( "20%2B1=21\r
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\n" ); document.write( "\n" ); document.write( "So the two page numbers are 20 and 21\r
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\n" ); document.write( "\n" ); document.write( "Check:\r
\n" ); document.write( "\n" ); document.write( "To check this answer, simply multiply the two numbers:\r
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\n" ); document.write( "\n" ); document.write( "20%2A21=420\r
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\n" ); document.write( "\n" ); document.write( "420=420
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