document.write( "Question 310853: Solve the trig equation sin2x = sqrt(3)sinx \n" ); document.write( "
Algebra.Com's Answer #225711 by J2R2R(94)\"\" \"About 
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Solve the trig equation sin(2x) = sqrt(3)sin(x)\r
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\n" ); document.write( "\n" ); document.write( "sin(2x) = 2 sin(x) cos(x)\r
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\n" ); document.write( "\n" ); document.write( "So we have\r
\n" ); document.write( "\n" ); document.write( "2 sin(x) cos(x) = sqrt(3) sin(x)\r
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\n" ); document.write( "\n" ); document.write( "We can cancel sin(x) from both sides which makes sin(x) = 0 a solution i.e. 0, 180, 360, etc.\r
\n" ); document.write( "\n" ); document.write( "2 cos(x) = sqrt(3) or cos(x) = sqrt(3)/2 giving x=30 and 330.\r
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\n" ); document.write( "\n" ); document.write( "So solutions in degrees in the range 0<=x<360 are\r
\n" ); document.write( "\n" ); document.write( "0, 30, 180 and 330\r
\n" ); document.write( "\n" ); document.write( "which shows there are four solutions for each 360 degrees range.\r
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\n" ); document.write( "\n" ); document.write( "N.B. bear in mind that a 360 degree range does not take both end points in its range since one end point is the other end point with 360 added to it.
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