document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=315387>Question 315387</A>: <I><SPAN STYLE=\"word-break: break-all;\"> John is traveling to a meeting that is 28 miles away.  He needs to be there in 30 minutes.  How fast does he need to go to make it to the meeting on time? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #225652 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=225652\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use the equation d=rt where d is the distance, r is the speed, and t is the time.\r<BR>\n" );
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document.write( "So we're given that \"a meeting that is 28 miles away. He needs to be there in 30 minutes.\", which means that d=28 and t=0.5 (30 minutes = 0.5 hours). Plug these values in to get: \r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=28=r%280.5%29 ALIGN=MIDDLE  ALT=\"28=r%280.5%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Now divide both sides by 0.5 and flip the equation to get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r=56 ALIGN=MIDDLE  ALT=\"r=56\"   DISABLED_style= \"max-width:90%; height:auto;\" >. So John needs to go 56 mph to go 28 miles in 30 minutes. </SPAN>\n" );
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