document.write( "Question 315101:  In a Gallup poll, 1025 randomly selected adults were surveyed and 29% of them said that they used the Internet for shopping at least a few times a year.
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document.write( "Find the margin of error.
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document.write( "Find a 99% confidence interval estimate of the percentage of adults who use the Internet for shopping. \n" );
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| Algebra.Com's Answer #225633 by stanbon(75887)      You can put this solution on YOUR website! In a Gallup poll, 1025 randomly selected adults were surveyed and 29% of them said that they used the Internet for shopping at least a few times a year. \n" ); document.write( "Find the margin of error. \n" ); document.write( "Find a 99% confidence interval estimate of the percentage of adults who use the Internet for shopping. \n" ); document.write( "-------------------------- \n" ); document.write( "sample proportion: 0.29 \n" ); document.write( "--- \n" ); document.write( "ME = (invT(0.995 with df = 1024)sqrt[0.29*0.71/1025] = 2.5806*0.0142 = 0.0366 \n" ); document.write( "--- \n" ); document.write( "99% CI: 0.29-0.0366 < p < 0.29+0.0366 \n" ); document.write( "============================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |