document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=315301>Question 315301</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a merchant has coffee worth 20 dollars a pound that she wishes to mix with with 60 pounds of coffee worth 90 dollars a pound to get a mixture that can be sold for eighty dollars a pound. How many pounds of twenty dollar offee should she use? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #225618 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=225618\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a merchant has coffee worth 20 dollars a pound that she wishes to mix with with 60 pounds of coffee worth 90 dollars a pound to get a mixture that can be sold for eighty dollars a pound. How many pounds of twenty dollar offee should she use?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "value + value = value<BR>\n" );
document.write( "20x + 90*60 = 80(x+60) dollars<BR>\n" );
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document.write( "20x + 90*60 = 80x + 80*60<BR>\n" );
document.write( "60x = 10*60<BR>\n" );
document.write( "x = 10 lbs (amt of 20 dollar coffee needed in the mix)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );