document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=315240>Question 315240</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A bicycle leaves town at 10mph at 8am and a car leaves at 11am, traveling in the same direction at 50mph. How many minutes after 11am will it be when the car overtakes the bike? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #225584 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=225584\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D=RT<BR>\n" );
document.write( "D=10T FOR THE CYCLIST<BR>\n" );
document.write( "D=50(T-3)<BR>\n" );
document.write( "10T=50(T-3)<BR>\n" );
document.write( "10T=50T-150<BR>\n" );
document.write( "10T-50T=-150<BR>\n" );
document.write( "-40T=-150<BR>\n" );
document.write( "T=-150/-40<BR>\n" );
document.write( "T=3.75 HOURS AFTER 8 AM THEY WILL MEET.<BR>\n" );
document.write( "8:00+3:45=11:45 OR 11:45 THE CAR WILL OVERTAKE THE CYCLIST.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );