document.write( "Question 315269: i need help with this Find an equation of the inverse relation.
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document.write( " a. 2x2 + 5y2 = 4\r
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document.write( " and \r
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document.write( " b. y = 3x2 – 5x + 9\r
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document.write( "Thanks so much \n" );
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Algebra.Com's Answer #225558 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Find an equation of the inverse relation. \n" ); document.write( "a. 2x2 + 5y2 = 4 \n" ); document.write( "--- \n" ); document.write( "Interchange 3x and y: \n" ); document.write( "2y^2 + 5x^2 = 4 \n" ); document.write( "Solve for \"y\": \n" ); document.write( "y^2 = -(5/2)x^2 + 2 \n" ); document.write( "--- \n" ); document.write( "y = sqrt[(-5/2)x^2+2)] or y = -sqrt[(-5/2)x^2+2] \n" ); document.write( "--------------------------------------- \n" ); document.write( "and \n" ); document.write( "b. y = 3x2 – 5x + 9 \n" ); document.write( "Interchange x and y: \n" ); document.write( "x = 3y^2 - 5y +9 \n" ); document.write( "3y^2 -5y + (9-x) \n" ); document.write( "Solve for \"y\": \n" ); document.write( "y = [5 +- sqrt(25 - 4*3(9-x))]/2 \n" ); document.write( "--- \n" ); document.write( "y = [5 + sqrt(25 - 4*3(9-x))]/2 or y = [5 - sqrt(25 - 4*3(9-x))]/2 \n" ); document.write( "============================================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |