document.write( "Question 315264: Based on the Nielsen ratings, the local CBS affiliate claims its 11:00 PM newscast reaches 41 % of the viewing audience in the area. In a survey of 100 viewers, 36% indicated that they watch the late evening news on this local CBS station.
\n" ); document.write( "30. What is the null hypothesis?
\n" ); document.write( "31. What is the alternate hypothesis?
\n" ); document.write( "32. What is the sample proportion?
\n" ); document.write( "33. What is the critical value if a = 0.01 ?
\n" ); document.write( "34. What is the z-statistic?
\n" ); document.write( "35. What is the critical value if the level of significance is 0.10?
\n" ); document.write( "36. What is your decision if a = 0.01
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #225544 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Based on the Nielsen ratings, the local CBS affiliate claims its 11:00 PM newscast reaches 41 % of the viewing audience in the area. In a survey of 100 viewers, 36% indicated that they watch the late evening news on this local CBS station.
\n" ); document.write( "------------\r
\n" ); document.write( "\n" ); document.write( "30. What is the null hypothesis?
\n" ); document.write( "Ho: p >= 0.41
\n" ); document.write( "Ha: p < 0.41
\n" ); document.write( "-------
\n" ); document.write( "31. What is the alternate hypothesis?
\n" ); document.write( "-----
\n" ); document.write( "32. What is the sample proportion?
\n" ); document.write( "sample proportion: 0.36
\n" ); document.write( "---------------------
\n" ); document.write( "33. What is the critical value if a = 0.01 ?
\n" ); document.write( "invNorm(0.01) = -2.3263
\n" ); document.write( "---------------------
\n" ); document.write( "34. What is the z-statistic?
\n" ); document.write( "z(0.36) = (0.36-0.41)/sqrt{0.41*0.59/100) = -1.0166
\n" ); document.write( "-------------------------
\n" ); document.write( "35. What is the critical value if the level of significance is 0.10?
\n" ); document.write( "invNorm(0.10) = -1.2816
\n" ); document.write( "-------------------------
\n" ); document.write( "36. What is your decision if a = 0.01
\n" ); document.write( "Since the test stat is not in the reject interval, fail to reject Ho.
\n" ); document.write( "=========================================================================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" ); document.write( "
\n" );