document.write( "Question 315214: solve. where appropriate, include approximations to the nearest thousandth. if no solution exists, state this \r
\n" ); document.write( "\n" ); document.write( "5^x = 125
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Algebra.Com's Answer #225508 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
You can solve using the concept of logs
\n" ); document.write( "The general rule is:
\n" ); document.write( "If \"a%5Eb+=+c\"
\n" ); document.write( "\"log%28a%2Cc%29+=+b\"
\n" ); document.write( "given:
\n" ); document.write( "\"5%5Ex+=+125\"
\n" ); document.write( "\"log%285%2C125%29+=+x\"
\n" ); document.write( "\"x+=+3\"
\n" ); document.write( "-------------
\n" ); document.write( "Another way is:
\n" ); document.write( "\"5%5Ex+=+125\"
\n" ); document.write( "\"5%5Ex+=+5%2A5%2A5\"
\n" ); document.write( "\"5%5Ex+=+5%5E3\"
\n" ); document.write( "\"x+=3\"
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