document.write( "Question 315125: If an object is propelled upward from a height of 96 feet at an initial velocity of 80 feet per second,then its height after t seconds is given by the equation h= -16t^2+80t+96 where h is in feet. After how many seconds will the object reach a height of 196 feet. \n" ); document.write( "
Algebra.Com's Answer #225424 by malaydassharma(59)\"\" \"About 
You can put this solution on YOUR website!
\"-16t%5E2%2B80t%2B96+=h\"\r
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\n" ); document.write( "\n" ); document.write( "OR \"16t%5E2-80t%2B100+=0\"\r
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"16x%5E2%2B-80x%2B100+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-80%29%5E2-4%2A16%2A100=0\".
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\n" ); document.write( " Discriminant d=0 is zero! That means that there is only one solution: \"x+=+%28-%28-80%29%29%2F2%5C16\".
\n" ); document.write( " Expression can be factored: \"16x%5E2%2B-80x%2B100+=+16%28x-2.5%29%2A%28x-2.5%29\"
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\n" ); document.write( " Again, the answer is: 2.5, 2.5.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+16%2Ax%5E2%2B-80%2Ax%2B100+%29\"

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