document.write( "Question 315070: The time to wait for a particular rural bus is distributed unifromly from 0 to 75 minutes. 100 riders are randomly sampled to learn how long they waited.\r
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document.write( "What is the 90th percentile sample average wait time (in minutes) for a sample of 100 riders?\r
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document.write( "mean = 0+75/2 = 37.5\r
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document.write( "I think I enter the numbers into my scientific calculator under distribution and inverse normal ( percentile, mean, stand dev. / square root of 100) or (.90, 37.5, ?)?? I can't figure out how to get the standard deviation....thank you thank you thank you \n" );
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Algebra.Com's Answer #225395 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The time to wait for a particular rural bus is distributed unifromly from 0 to 75 minutes. 100 riders are randomly sampled to learn how long they waited. \n" ); document.write( "What is the 90th percentile sample average wait time (in minutes) for a sample of 100 riders? \n" ); document.write( "mean = 0+75/2 = 37.5 \n" ); document.write( "I think I enter the numbers into my scientific calculator under distribution and inverse normal ( percentile, mean, stand dev. / square root of 100) or (.90, 37.5, ?)?? \n" ); document.write( "------------------------- \n" ); document.write( "I can't figure out how to get the standard deviation.... \n" ); document.write( "Comment: Please consider this. The range of the data is generally \n" ); document.write( "considered to 6sigma. Your data range is 0 to 75. \n" ); document.write( "If 6sigma = 75, sigma = 12.5 \n" ); document.write( "================================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |