document.write( "Question 315037: at noon a private plane left Austin for Los Angeles,2300km away,flying at 500km/h. one hour later a jet left Los Angeles for Austin at 700km/h. at what time did they pass each other? \n" ); document.write( "
Algebra.Com's Answer #225374 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! at noon a private plane left Austin for Los Angeles, 2300km away, flying at 500km/h. \n" ); document.write( "one hour later a jet left Los Angeles for Austin at 700km/h. \n" ); document.write( "at what time did they pass each other? \n" ); document.write( ": \n" ); document.write( "Let t = travel time of the private plane \n" ); document.write( "then \n" ); document.write( "(t-1) = travel time of the jet \n" ); document.write( ": \n" ); document.write( "When the aircraft meet, the sum of their distances will be 2300 km \n" ); document.write( "Write a dist equation; dist = speed * time \n" ); document.write( ": \n" ); document.write( "jet dist + private dist = 2300 km \n" ); document.write( "700(t-1) + 500t = 2300 \n" ); document.write( ": \n" ); document.write( "700t - 700 + 500t = 2300 \n" ); document.write( ": \n" ); document.write( "1200t = 2300 + 700 \n" ); document.write( ": \n" ); document.write( "1200t = 3000 \n" ); document.write( "t = \n" ); document.write( "t = 2.5 hrs \n" ); document.write( ": \n" ); document.write( "12:00 + 2:30 = 2:30 PM the planes will meet \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Confirm solution by finding the distance \n" ); document.write( "2.5(500) = 1250 \n" ); document.write( "1.5(700) = 1050 \n" ); document.write( "--------------- \n" ); document.write( "total dist 2300 \n" ); document.write( " |