document.write( "Question 315028: Dianne was given $35,000 when she retired. she invested some at 7% interest and the rest at 9% interest. if she earned $2,910 in interest in one year, how much was invested in each account? \n" ); document.write( "
Algebra.Com's Answer #225335 by checkley77(12844)\"\" \"About 
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.09x+.07(35,000-x)=2,910
\n" ); document.write( ".09x+2,450-.07x=2,910
\n" ); document.write( ".02x=2,910-2,450
\n" ); document.write( ".02x=460
\n" ); document.write( "x=460/.02
\n" ); document.write( "23,000 invested @ 8%
\n" ); document.write( "35,000-23,000=12,000 invested @ 7%
\n" ); document.write( "Proof:
\n" ); document.write( ".09*23,000+.07*12,000=2,910
\n" ); document.write( "2,070+840=2,910
\n" ); document.write( "1,910=2,910
\n" ); document.write( "
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