document.write( "Question 314863: Assume that adults have IQ scored that are normally distributed with a mean of 100 and a standard deviation of 15. Find the probabilty that a randomly selveted adult has an IQ between 81 and 119? I can't find thee formula on how to find the answer. \n" ); document.write( "
Algebra.Com's Answer #225302 by Fombitz(32388)\"\" \"About 
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Find the z scores for both values.
\n" ); document.write( "\"z=%28x-mu%29%2Fsigma\"
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\n" ); document.write( "\"z1=%2881-100%29%2F15=-1.267\"
\n" ); document.write( "\"z2=%28119-100%29%2F15=1.267\"
\n" ); document.write( "Find the normal probability value for both of these z scores.
\n" ); document.write( "I used EXCEL's NORMDIST function(CUMULATIVE=TRUE).
\n" ); document.write( "\"P1=0.1026237\"
\n" ); document.write( "\"P2=0.897363\"
\n" ); document.write( "The probability for the values to lie between 81 and 119 is the difference in probability values.
\n" ); document.write( "\"P=0.897363-0.1026237\"
\n" ); document.write( "\"P=highlight_green%280.795%29\"
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