document.write( "Question 314848: A bag contains some balls of which 1/4 are red. forty more balls of which 5 are red are added. if 1/5 of all the balls are red, how many balls were there originally? \n" ); document.write( "
Algebra.Com's Answer #225296 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Originally you had \"4N\" balls, \"N\" of them were red.
\n" ); document.write( "\"5\" red balls and \"35\" non-red balls are now added.
\n" ); document.write( "The total number of red balls is now \"N%2B5\"
\n" ); document.write( "The total number of balls is \"4N%2B40\".
\n" ); document.write( "(1/5) of the new total are red.
\n" ); document.write( "\"%281%2F5%29%284N%2B40%29=N%2B5\"
\n" ); document.write( "\"4N%2B40=5N%2B25\"
\n" ); document.write( "\"N=40-25\"
\n" ); document.write( "\"highlight%28N=15%29\"
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "Verify.
\n" ); document.write( "You originally had 15 red balls, and 60 total balls (15/60=1/4).
\n" ); document.write( "Then you added the additional balls.
\n" ); document.write( "You then had 20 red balls and 100 total balls (20/100=1/5).
\n" ); document.write( "
\n" );