document.write( "Question 314961: The width of a rectangle is 3 feet, and the diagonal is 5 feet. What is the area of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #225284 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The width of the rectangle which is known to be 3 feet, the unknown length of the rectangle, and the diagonal that measures 5 feet form a right triangle. 3-4-5 is a Pythagorean Triple, therefore the missing side of the rectangle must measure 4 feet. The area of the rectangle is the length times the width, so 3 times 4 is 12 square feet.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |