document.write( "Question 36677: find the verical and horizontal asymptotes of the following functions:
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document.write( "1) f(x)=(2x^2+5x^2-3)/(x^2+2)
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document.write( "2) f(x)=1/(x-3)^2\r
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document.write( "thank you \n" );
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Algebra.Com's Answer #22523 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! find the verical and horizontal asymptotes of the following functions: \n" ); document.write( "1) f(x)=(2x^2+5x^2-3)/(x^2+2)\r \n" ); document.write( "\n" ); document.write( "Did you mean to have two \"x^2\" terms? \n" ); document.write( "Horizontal Asymptotes depends on your answer to that question. \n" ); document.write( "If you meant 2x^2+5x-3 in the numerator, you have a horizontal \n" ); document.write( "asymptote at y=2. \n" ); document.write( "If you menat 2x^2+5x^2-3 = 7x^2-3 as the numerator, you have a \n" ); document.write( "horizontal asymptote at y=7. \n" ); document.write( "Vertical Asymptotes: \n" ); document.write( "When/If the denominator is zero. But x^2+2 cannot be zero. So, \n" ); document.write( "no Vertical asymptotes.\r \n" ); document.write( "\n" ); document.write( "2) f(x)=1/(x-3)^2 \n" ); document.write( "Horzontal Asymptotes: none \n" ); document.write( "Vertical Asymptotes: When (x-3)^2=0 \n" ); document.write( "When x=3 \n" ); document.write( "Therefore: Vertical asymptote at x=3 \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |