document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=314886>Question 314886</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do I solve log base 6 of 12? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #225217 by </B><A HREF=/tutors/aboutme.mpl?userid=CharlesG2><B>CharlesG2(834)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CharlesG2><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=225217\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how do I solve log base 6 of 12?\r<BR>\n" );
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document.write( "log6 (12)<BR>\n" );
document.write( "you could convert the log to base 10 using the conversion of base formula<BR>\n" );
document.write( "logb (x) = logk (x) / logk (b), where b is old base, and k is new base<BR>\n" );
document.write( "log6 (12) = log10 (12)/ log10 (6)<BR>\n" );
document.write( "the answer is 1.3869 to 4 places\r<BR>\n" );
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