document.write( "Question 314865: A can finish a work in 6 days whereas B can finish the work in 9 days.If both of them work together,what is the probability that the work will be finished on third day? \n" ); document.write( "
Algebra.Com's Answer #225213 by CharlesG2(834)![]() ![]() ![]() You can put this solution on YOUR website! A can finish a work in 6 days whereas B can finish the work in 9 days.If both of them work together,what is the probability that the work will be finished on third day?\r \n" ); document.write( "\n" ); document.write( "A --> 1 job / 6 days = 1/6 job per day \n" ); document.write( "B --> 1 job / 9 days = 1/9 job per day \n" ); document.write( "A + B = 1 job / (1/6 job/day + 1/9 job/day) \n" ); document.write( "A + B = 1 job / (9/54 + 6/54 job/day) \n" ); document.write( "A + B = 1 job / (15/54 job/day) \n" ); document.write( "A + B = 1 job * 54/15 days/job = 54/15 day/job * job \n" ); document.write( "A + B = 18/5 days = 3.6 days \n" ); document.write( "takes A and B 3.6 days to do it together, \n" ); document.write( "if they had finished on the first day answer would be <= 1, \n" ); document.write( "if 2nd day answer would be >1 and <= 2, \n" ); document.write( "if 3rd day answer would be >2 and <= 3, \n" ); document.write( "so they finished on the 4th day, so probability that work will be finished on the 3rd day is 0\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |