document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=314811>Question 314811</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the measure of the supplement of 120 degrees.\r<BR>\n" );
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document.write( "Find the measure of the supplement of 60 degrees. \r<BR>\n" );
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document.write( "Find the measure of the complement of 3 degrees. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #225156 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=225156\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Supplement of 120 degrees = 180 - 120 or 60 degrees.\r<BR>\n" );
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document.write( "Supplement of 60 degrees = 180 - 60 or 120 degrees.\r<BR>\n" );
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document.write( "Complement of 60 degrees = 90 - 3 or 87 degrees. </SPAN>\n" );
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