document.write( "Question 314801: how many gallons of a 40% antifreeze solution and a 70% antifreeze solution must be mixed to get 24 gallons of a 50% antifreeze solution? \n" ); document.write( "

Algebra.Com's Answer #225140 by Fombitz(32388) $\"\"$ $\"About$

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1. $\"40X%2B70Y=50%2824%29\"$
\n" ); document.write( "2. $\"X%2BY=24\"$
\n" ); document.write( "Multiply eq. by -40 and add to eq. 1,
\n" ); document.write( " $\"40X%2B70Y-40X-40Y=1200-960\"$
\n" ); document.write( " $\"30Y=240\"$
\n" ); document.write( " $\"Y=8\"$
\n" ); document.write( "Then from eq. 2,
\n" ); document.write( " $\"X%2B8=24\"$
\n" ); document.write( " $\"X=16\"$
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\n" ); document.write( "16 gallons of 40% solution and 8 gallons of 70% solution. \n" ); document.write( "

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