document.write( "Question 314751: A ship is traveling at a abearing of 60 degrees for 3 miles then turns and travels at a bearaing of 150 degres for 2 miles then returns to where it started. Find the distance traveled by the ship.\r
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document.write( "I am having a hard time even starting this problem. I tried drawing a 30 degree angle (using \"North\" as the terminal side and the 3 miles along the side that I drew going northeast). I thought I would use the Law of Sines or Cosines but I can't even begin the problem!\r
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document.write( "Thank you! \n" );
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Algebra.Com's Answer #225133 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! Break up the ship's travel into x and y components. \n" ); document.write( "3 miles at 60=( \n" ); document.write( "2 miles at 150=( \n" ); document.write( "At this point the ship's position is \n" ); document.write( "(1.5-1.732,2.598+1.0)=(-0.232,3.598) \n" ); document.write( "In order to return back the ship will have to travel \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The total distance the ship travels is then, \n" ); document.write( " |