document.write( "Question 314788: Suppose that the weight of apples eaten by individual Americans can be described by a normal probability distribution with mean μ = 15 pounds and standard deviation σ = 5 pounds per < year. \r
\n" ); document.write( "\n" ); document.write( "For a random sample of n = 16 people, what is the standard deviation of the sampling distribution of the sample mean ̄x? \r
\n" ); document.write( "\n" ); document.write( "For a random sample of n = 16 people, what is the mean of the sampling distribution of the sample mean ̄x? \r
\n" ); document.write( "\n" ); document.write( "For a random sample of n = 16 people, what is the z-score for a sample mean ̄x = 10 pounds? \r
\n" ); document.write( "\n" ); document.write( "For a random sample of n = 9 people, what is the z-score for a sample mean ̄x = 18 pounds?
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Algebra.Com's Answer #225124 by stanbon(75887)\"\" \"About 
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Suppose that the weight of apples eaten by individual Americans can be described by a normal probability distribution with mean μ = 15 pounds and standard deviation σ = 5 pounds per < year.
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\n" ); document.write( "For a random sample of n = 16 people, what is the standard deviation of the sampling distribution of the sample mean ̄x?
\n" ); document.write( "Ans: 5/Sqrt(16) = 5/4
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\n" ); document.write( "For a random sample of n = 16 people, what is the mean of the sampling distribution of the sample mean ̄x?
\n" ); document.write( "Ans: x-bar = 15
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\n" ); document.write( "For a random sample of n = 16 people, what is the z-score for a sample mean ̄x = 10 pounds?
\n" ); document.write( "z(10) = (10-15)/[5/sqrt(16)] = -5/(5/4) = -4
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\n" ); document.write( "For a random sample of n = 9 people, what is the z-score for a sample mean ̄x = 18 pounds?
\n" ); document.write( "z(18) = (18-15)/[5/sqrt(3)] = 3/(5/sqrt(3)) = 3*sqrt(3)/5 = 1.0392
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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