document.write( "Question 314750: Suppose a population of initial size 100 grows at the rate of 8% per year forever.
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document.write( "What is the size of the population at the end of year 1?
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document.write( "What is the size of the population at the end of year 2?
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document.write( "What is the size of the population at the end of year 3?
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document.write( "what is the size of the population at the end of year n (for any integer n)?
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document.write( "What algebraic equation would you need to solve to find the number of years x that it would take for our population to reach 200 \n" );
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Algebra.Com's Answer #225115 by Jstrasner(112)![]() ![]() You can put this solution on YOUR website! hey,\r \n" ); document.write( "\n" ); document.write( "Well the initial equation would be:\r \n" ); document.write( "\n" ); document.write( "S(size)n=100(1.08^n)\r \n" ); document.write( "\n" ); document.write( "So for the first year:\r \n" ); document.write( "\n" ); document.write( "S1= 100(1.08^1)= 108 people \n" ); document.write( "S2= 100(1.08^2)= 116.64 => so 117 people roughly \n" ); document.write( "S3= 100(1.08^3)= 125.97 => so 126 people roughly\r \n" ); document.write( "\n" ); document.write( "As shown above the size at n years is :\r \n" ); document.write( "\n" ); document.write( "100(1.08^n)\r \n" ); document.write( "\n" ); document.write( "As for the algebraic equation:\r \n" ); document.write( "\n" ); document.write( "we would use the one above:\r \n" ); document.write( "\n" ); document.write( "200 = 100(1.08^n) \n" ); document.write( "and you would use log\r \n" ); document.write( "\n" ); document.write( "I hope this helps! \n" ); document.write( " |