document.write( "Question 35931: Please help, We included the table of numbers that we have chosen. Any help, especially with graphing the answer would be highly appreciated. Thank you.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "When using the quadratic formula to solve a quadratic equation ax2 + bx + c = 0, the discriminate is b2 - 4ac. This discriminate can be positive, zero, or negative. (When the discriminate is negative, then we have the square root of a negative number. This is called an imaginary number, sqrt(-1) = i. )
\n" ); document.write( "• Explain what the value of the discriminate means to the graph of y = ax2 + bx + c. Hint: Chose values of a, b and c to create a particular discriminate. Then, graph the corresponding equation.
\n" ); document.write( "DISCRIMINATE: b^2-4ac\r
\n" ); document.write( "\n" ); document.write( " A B C Discriminate
\n" ); document.write( "b^2-4ac
\n" ); document.write( "2 6 4 4
\n" ); document.write( "9 6 3 144
\n" ); document.write( " 1 5 3 13
\n" ); document.write( "4 10 7 -12 {-3.4}
\n" ); document.write( "

Algebra.Com's Answer #22510 by venugopalramana(3286)\"\" \"About 
You can put this solution on YOUR website!
SEE THE FOLLOWING AND TRY
\n" ); document.write( "When using the quadratic formula to solve a quadratic equation ax2 + bx + c = 0, the discriminant is b2 - 4ac. This discriminant can be positive, zero, or negative. (When the discriminate is negative, then we have the square root of a negative number. This is called an imaginary number, sqrt(-1) = i. )
\n" ); document.write( "Explain what the value of the discriminant means to the graph of y = ax2 + bx + c. Hint: Chose values of a, b and c to create a particular discriminant. Then, graph the corresponding equation.
\n" ); document.write( "CASE 1....DISCRIMINANT (D SAY) IS POSITIVE.....
\n" ); document.write( "EX..LET Y = X^2-5X+6=0..
\n" ); document.write( "D=5^2-4*1*6=25-24=1...
\n" ); document.write( "HENCE ROOTS ARE
\n" ); document.write( "REAL,THAT IS THE GRAPH CUTS THE X AXIS AT 2 REAL POINTS
\n" ); document.write( "DISTINCT ...2 AND 3
\n" ); document.write( "AND THE FUNCTION Y COULD BE POSITIVE OR NEGATIVE WITH A MAXIMUM OR MINIMUM
\n" ); document.write( "SEE GRAPH BELOW
\n" ); document.write( "\"+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+x%5E2-5x%2B6%29+\"
\n" ); document.write( "CASE 2.....D=0
\n" ); document.write( "EX....LET...Y=X^2-2X+1=0
\n" ); document.write( "D=2^2-4*1*1=4-4=0
\n" ); document.write( "HENCE ROOTS ARE
\n" ); document.write( "REAL.THAT IS THE GRAPH CUTS THE X AXIS AT 1 REAL POINT.
\n" ); document.write( "EQUAL...1 AND 1
\n" ); document.write( "AND THE FUNCTION Y IS ALWAYS NON NEGATIVE OR NON POSITIVE DEPENDING ON THE SIGN OF COEFFICIENT OF X^2 BEING POSITIVE OR NEGATIVE , WITH A MINIMUM OR MAXIMUM VALUE OF ZERO.
\n" ); document.write( "SEE GRAPH BELOW.
\n" ); document.write( "\"+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+x%5E2-2x%2B1%29+\"
\n" ); document.write( "CASE 3.......D IS NEGATIVE
\n" ); document.write( "EX....LET Y = X^2+X+1=0
\n" ); document.write( "D=1^2-4*1*1=1-4=-3
\n" ); document.write( "HENCE ROOTS ARE
\n" ); document.write( "IMAGINARY.THAT IS THE GRAPH DOES NOT CUT THE X AXIS.
\n" ); document.write( "DISTINCT.....(-1+iSQRT(3))/2....AND (-1-iSQRT(3))/2
\n" ); document.write( "AND THE FUNCTION Y IS ALWAYS POSITIVE SINCE COEFFICIENT OF X^2 IS POSITIVE.
\n" ); document.write( "SEE THE GRAPH BELOW...
\n" ); document.write( "\"+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+x%5E2%2Bx%2B1%29+\"
\n" ); document.write( "
\n" ); document.write( "EX....LET Y = -X^2+X-1=0
\n" ); document.write( "D=1^2-4*(-1)*(-1)=1-4=-3
\n" ); document.write( "HENCE ROOTS ARE
\n" ); document.write( "IMAGINARY.THAT IS THE GRAPH DOES NOT CUT THE X AXIS.
\n" ); document.write( "DISTINCT.....(1-iSQRT(3))/2....AND (1+iSQRT(3))/2
\n" ); document.write( "AND THE FUNCTION Y IS ALWAYS NEGATIVE SINCE COEFFICIENT OF X^2 IS NEGATIVE.
\n" ); document.write( "SEE THE GRAPH BELOW...
\n" ); document.write( "\"+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+-x%5E2%2Bx-1%29+\"
\n" ); document.write( "
\n" );