document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=36317>Question 36317</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (a):  	Find the equation of the line joining the points<BR>\n" );
document.write( "		(&#9472;5, 2, 3) and (5, &#9472; 2, 3).			                   <BR>\n" );
document.write( "(b)	Find the equation of the sphere, which contains the circle<BR>\n" );
document.write( "	x2 + y2 + z2 = 9, 3x + 3y + 3z = 5   and<BR>\n" );
document.write( "	passes through the origin.				              </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #22507 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=22507\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a): Find the equation of the line joining the points<BR>\n" );
document.write( "(&#9472;5, 2, 3) and (5, &#9472; 2, 3).<BR>\n" );
document.write( "EQN.IS GIVEN BY (X-X1)/(X2-X1)=(Y-Y1)/(Y2-Y1)=(Z-Z1)/(Z2-Z1)<BR>\n" );
document.write( "(X+5)/(5+5)=(Y-2)/(-2-2)=(Z-3)/(3-3)<BR>\n" );
document.write( "HENCE EQN.OF LINE IS <BR>\n" );
document.write( "(X+5)/10=-(Y-2)/4 AND Z=3<BR>\n" );
document.write( "4X+20=-10Y+20<BR>\n" );
document.write( "4X+10Y=0 AND Z=3\r<BR>\n" );
document.write( "\n" );
document.write( "(b) Find the equation of the sphere, which contains the circle<BR>\n" );
document.write( "x2 + y2 + z2 = 9, 3x + 3y + 3z = 5 and<BR>\n" );
document.write( "passes through the origin. \r<BR>\n" );
document.write( "\n" );
document.write( "EQN. OF ANY SPHERE THROUGH ABOVE CIRCLE IS <BR>\n" );
document.write( "(X^2+Y^2+Z^2-9)+K(3X+3Y+3Z-5)=0...IT PASSES THROUGH ORIGIN(0,0,0)..SO<BR>\n" );
document.write( "-9-5K=0<BR>\n" );
document.write( "K=-9/5<BR>\n" );
document.write( "HENCE EQN.OF SPHERE IS BY SUBSTITITING FOR K AND SIMPLIFYING<BR>\n" );
document.write( "5X^2+5Y^2+5Z^2-27X-27Y-27Z=0 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );