document.write( "Question 314627: Walt made an extra $7000 last year from a part-time job. He invested part of the money at 8% and the rest at 6%. He made a total of $500 in interest. How much wasinvested at 6%? \n" ); document.write( "
Algebra.Com's Answer #225060 by checkley77(12844)\"\" \"About 
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.08X+.06(7,000-X)=500
\n" ); document.write( ".08X+420-.06X=500
\n" ); document.write( ".02X=500-420
\n" ); document.write( ".02X=80
\n" ); document.write( "X=80/.02
\n" ); document.write( "X=4,000 AMOUNT INVESTED @ 8%.
\n" ); document.write( "7,000-4,000=3,000 AMOUNT INVESTED @ 6%.
\n" ); document.write( "PROOF:
\n" ); document.write( ".08*4,000+.06*3,000=500
\n" ); document.write( "320+180=500
\n" ); document.write( "500=500
\n" ); document.write( "
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